Number Series Methods Short Cut Tricks Problems and Solutions Math Tricks

Number Series Methods Short Cut Tricks Problems & Solutions Math Tricks:

Number Series is the most commonly asked topics in any competitive exam like SBI, IBPS, NABARD, SSC, RPSC, UPSC and many other state and central exams. Here we are discussing on the Number System problems and Solutions. There are various methods available for Number Series.

Number Series: Number Series can be said as a form of numbers in a certain sequence, where some numbers are mistakenly put into the series of numbers and some numbers missing in the series. Number Series was the perfect school time math topics. Here we are providing the some examples.

Perfect Square Series: Perfect Square Series are based on square of a number which is in same order and one square number is missing in that given series.

Like: 441, 484, 529, 576, ?

Perfect Cube Series: The Perfect Cube Series are based on a cube number which is in same order and one Cube Number is missing the series.

Like: 1331, 1728, 2179, ?

Ration Series: The ratio series depends on Ratio series, where sequence is in the form of ratio difference between numbers.

Geometric Series: The Geometric Series depends on ascending and descending sequence of numbers and each number is obtaining by multiplying and dividing the preceding number with static number.

Like: 5, 45, 405, 3645, ?

Number Series Methods Short Tricks Questions and Answers According to Previous Year Question Papers??

Question 1: Find Out Missing Number of Square Series of 441, 484, 529, 576, ?

Solution: 441=212,  484=222, 523= 232 , 576= 242, 625=252

Question 2: Find Out the Missing Number in the Given Sequence of Numbers 121, 144, 169, ?, 225 ??

Solution: 121= 112, 144=122, 169= 132, 196=142, 225=152

Answer= 14

Question 3: Find Out the Missing Cube Number in the Series 3375, ?, 24389, 46656, 79507??

Solution: 153, 223, 293, 363, 433

Answer: 22

Question 4: Find Out the Missing Number in the Cube Series 1000, 8000, 27000, 64000, ??

Solution: 103, 203, 303, 403, 503

Answer= 50

Question 5: If A:B=3:7 and B:C=5:9, then A:B:C=?

Solution: A:B=3:7


= (5X7/5): (9X7/5)=7:63/5

=A:B:C=3:7:63/5= 15: 35:63

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